Top Array और String समस्याएँ

#include <iostream>
#include <unordered_map>
using namespace std;
int main() {
	int arr[] = {2,7,11,15}, target = 9;
	unordered_map<int,int> seen;
	for (int i = 0; i < 4; i++) {
		if (seen.count(target - arr[i])) { cout << "Indices: " << seen[target-arr[i]] << "," << i; break; }
		seen[arr[i]] = i;
	}
	return 0;
}

import java.util.*;
public class Main {
	public static void main(String[] args) {
		int[] arr = {2,7,11,15};
		int target = 9;
		Map<Integer,Integer> seen = new HashMap<>();
		for (int i = 0; i < 4; i++) {
			if (seen.containsKey(target - arr[i])) { System.out.println("Indices: " + seen.get(target-arr[i]) + "," + i); break; }
			seen.put(arr[i], i);
		}
	}
}

arr = [2,7,11,15]
target = 9
seen = {}
for i, x in enumerate(arr):
    if target - x in seen:
        print(f"Indices: {seen[target-x]},{i}")
        break
    seen[x] = i

#include <stdio.h>
int main() {
	int arr[] = {2,7,11,15}, target = 9;
	for (int i = 0; i < 4; i++)
		for (int j = i+1; j < 4; j++)
			if (arr[i]+arr[j] == target) { printf("Indices: %d,%d", i, j); return 0; }
	return 0;
}

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#include <iostream>
using namespace std;
int main() {
	int arr[] = {3,7,1,9,4};
	int mx = arr[0], mn = arr[0];
	for (int i = 1; i < 5; i++) { if (arr[i] > mx) mx = arr[i]; if (arr[i] < mn) mn = arr[i]; }
	cout << "Max: " << mx << " Min: " << mn;
	return 0;
}

public class Main {
	public static void main(String[] args) {
		int[] arr = {3,7,1,9,4};
		int mx = arr[0], mn = arr[0];
		for (int i = 1; i < 5; i++) { if (arr[i] > mx) mx = arr[i]; if (arr[i] < mn) mn = arr[i]; }
		System.out.println("Max: " + mx + " Min: " + mn);
	}
}

arr = [3,7,1,9,4]
mx = mn = arr[0]
for x in arr[1:]:
    if x > mx: mx = x
    if x < mn: mn = x
print("Max:", mx, "Min:", mn)

#include <stdio.h>
int main() {
	int arr[] = {3,7,1,9,4};
	int mx = arr[0], mn = arr[0];
	for (int i = 1; i < 5; i++) { if (arr[i] > mx) mx = arr[i]; if (arr[i] < mn) mn = arr[i]; }
	printf("Max: %d Min: %d", mx, mn);
	return 0;
}

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#include <iostream>
using namespace std;
int main() {
	int arr[] = {5,3,8,1,9}, target = 8;
	for (int i = 0; i < 5; i++) if (arr[i] == target) { cout << "Found at index " << i << " in O(n)"; break; }
	return 0;
}

public class Main {
	public static void main(String[] args) {
		int[] arr = {5,3,8,1,9};
		int target = 8;
		for (int i = 0; i < 5; i++) if (arr[i] == target) { System.out.println("Found at index " + i + " in O(n)"); break; }
	}
}

arr = [5,3,8,1,9]
target = 8
for i, x in enumerate(arr):
    if x == target:
        print(f"Found at index {i} in O(n)")
        break

#include <stdio.h>
int main() {
	int arr[] = {5,3,8,1,9}, target = 8;
	for (int i = 0; i < 5; i++) if (arr[i] == target) { printf("Found at index %d in O(n)", i); break; }
	return 0;
}

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#include <iostream>
using namespace std;
int main() {
	string s1 = "listen", s2 = "silent";
	int freq[26] = {0};
	for (char c : s1) freq[c-'a']++;
	for (char c : s2) freq[c-'a']--;
	bool isAnagram = true;
	for (int i = 0; i < 26; i++) if (freq[i] != 0) isAnagram = false;
	cout << "'" << s1 << "' and '" << s2 << "' are anagrams: " << isAnagram;
	return 0;
}

public class Main {
	public static void main(String[] args) {
		String s1 = "listen", s2 = "silent";
		int[] freq = new int[26];
		for (char c : s1.toCharArray()) freq[c-'a']++;
		for (char c : s2.toCharArray()) freq[c-'a']--;
		boolean isAnagram = true;
		for (int f : freq) if (f != 0) isAnagram = false;
		System.out.println("'" + s1 + "' and '" + s2 + "' are anagrams: " + isAnagram);
	}
}

from collections import Counter
s1, s2 = "listen", "silent"
print(f"'{s1}' and '{s2}' are anagrams: {Counter(s1) == Counter(s2)}")

#include <stdio.h>
int main() {
	char s1[] = "listen", s2[] = "silent";
	int freq[26] = {0};
	for (int i = 0; s1[i]; i++) freq[s1[i]-'a']++;
	for (int i = 0; s2[i]; i++) freq[s2[i]-'a']--;
	int isAnagram = 1;
	for (int i = 0; i < 26; i++) if (freq[i] != 0) isAnagram = 0;
	printf("'%s' and '%s' are anagrams: %s", s1, s2, isAnagram ? "true" : "false");
	return 0;
}

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#include <iostream>
using namespace std;
int main() {
	cout << "Get brute force working first, then look for repeated work a better approach can eliminate";
	return 0;
}

public class Main {
	public static void main(String[] args) {
		System.out.println("Get brute force working first, then look for repeated work a better approach can eliminate");
	}
}

print("Get brute force working first, then look for repeated work a better approach can eliminate")

#include <stdio.h>
int main() {
	printf("Get brute force working first, then look for repeated work a better approach can eliminate");
	return 0;
}

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