Anagram और Frequency Count

#include <iostream>
#include <algorithm>
using namespace std;
int main() {
    string a = "listen", b = "silent";
    string sa = a, sb = b;
    sort(sa.begin(), sa.end()); sort(sb.begin(), sb.end());
    cout << (sa == sb ? "Anagrams" : "Not anagrams") << endl;
    return 0;
}

import java.util.Arrays;
public class Main {
    public static void main(String[] args) {
        char[] a = "listen".toCharArray(), b = "silent".toCharArray();
        Arrays.sort(a); Arrays.sort(b);
        System.out.println(Arrays.equals(a, b) ? "Anagrams" : "Not anagrams");
    }
}

a, b = "listen", "silent"
print("Anagrams" if sorted(a) == sorted(b) else "Not anagrams")

#include <stdio.h>
#include <string.h>
#include <stdlib.h>
int cmp(const void *a, const void *b) { return *(char*)a - *(char*)b; }
int main() {
    char a[] = "listen", b[] = "silent";
    qsort(a, strlen(a), 1, cmp);
    qsort(b, strlen(b), 1, cmp);
    printf("%s\n", strcmp(a, b) == 0 ? "Anagrams" : "Not anagrams");
    return 0;
}

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#include <iostream>
#include <map>
using namespace std;
int main() {
    string s = "banana";
    map<char, int> freq;
    for (char c : s) freq[c]++;
    for (auto& p : freq) cout << p.first << ": " << p.second << endl;
    return 0;
}

import java.util.TreeMap;
public class Main {
    public static void main(String[] args) {
        String s = "banana";
        TreeMap<Character, Integer> freq = new TreeMap<>();
        for (char c : s.toCharArray()) freq.put(c, freq.getOrDefault(c, 0) + 1);
        for (var e : freq.entrySet()) System.out.println(e.getKey() + ": " + e.getValue());
    }
}

s = "banana"
freq = {}
for c in s:
    freq[c] = freq.get(c, 0) + 1
for c, n in sorted(freq.items()):
    print(f"{c}: {n}")

#include <stdio.h>
#include <string.h>
int main() {
    char s[] = "banana";
    int freq[26] = {0};
    for (int i = 0; i < strlen(s); i++) freq[s[i] - 'a']++;
    for (int i = 0; i < 26; i++) if (freq[i]) printf("%c: %d\n", 'a' + i, freq[i]);
    return 0;
}

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#include <iostream>
using namespace std;
int main() {
    string s = "hello world";
    int freq[26] = {0};
    for (char c : s) if (c >= 'a' && c <= 'z') freq[c - 'a']++;
    cout << "'l' count: " << freq['l' - 'a'] << endl;
    return 0;
}

public class Main {
    public static void main(String[] args) {
        String s = "hello world";
        int[] freq = new int[26];
        for (char c : s.toCharArray()) if (c >= 'a' && c <= 'z') freq[c - 'a']++;
        System.out.println("'l' count: " + freq['l' - 'a']);
    }
}

s = "hello world"
freq = [0] * 26
for c in s:
    if 'a' <= c <= 'z':
        freq[ord(c) - ord('a')] += 1
print("'l' count:", freq[ord('l') - ord('a')])

#include <stdio.h>
#include <string.h>
int main() {
    char s[] = "hello world";
    int freq[26] = {0};
    for (int i = 0; i < strlen(s); i++) if (s[i] >= 'a' && s[i] <= 'z') freq[s[i] - 'a']++;
    printf("'l' count: %d\n", freq['l' - 'a']);
    return 0;
}

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#include <iostream>
using namespace std;
int main() {
    string a = "anagram", b = "nagaram";
    int freq[26] = {0};
    for (char c : a) freq[c - 'a']++;
    for (char c : b) freq[c - 'a']--;
    bool isAnagram = true;
    for (int i = 0; i < 26; i++) if (freq[i] != 0) isAnagram = false;
    cout << (isAnagram ? "Anagrams" : "Not anagrams") << endl;
    return 0;
}

public class Main {
    public static void main(String[] args) {
        String a = "anagram", b = "nagaram";
        int[] freq = new int[26];
        for (char c : a.toCharArray()) freq[c - 'a']++;
        for (char c : b.toCharArray()) freq[c - 'a']--;
        boolean isAnagram = true;
        for (int f : freq) if (f != 0) isAnagram = false;
        System.out.println(isAnagram ? "Anagrams" : "Not anagrams");
    }
}

a, b = "anagram", "nagaram"
freq = [0] * 26
for c in a:
    freq[ord(c) - ord('a')] += 1
for c in b:
    freq[ord(c) - ord('a')] -= 1
print("Anagrams" if all(f == 0 for f in freq) else "Not anagrams")

#include <stdio.h>
#include <string.h>
int main() {
    char a[] = "anagram", b[] = "nagaram";
    int freq[26] = {0}, isAnagram = 1;
    for (int i = 0; i < strlen(a); i++) freq[a[i] - 'a']++;
    for (int i = 0; i < strlen(b); i++) freq[b[i] - 'a']--;
    for (int i = 0; i < 26; i++) if (freq[i] != 0) isAnagram = 0;
    printf("%s\n", isAnagram ? "Anagrams" : "Not anagrams");
    return 0;
}

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#include <iostream>
using namespace std;
int main() {
    string s = "programming";
    int freq[26] = {0};
    for (char c : s) freq[c - 'a']++;
    int best = 0;
    for (int i = 1; i < 26; i++) if (freq[i] > freq[best]) best = i;
    cout << "Most common: '" << (char)('a' + best) << "' (" << freq[best] << " times)" << endl;
    return 0;
}

public class Main {
    public static void main(String[] args) {
        String s = "programming";
        int[] freq = new int[26];
        for (char c : s.toCharArray()) freq[c - 'a']++;
        int best = 0;
        for (int i = 1; i < 26; i++) if (freq[i] > freq[best]) best = i;
        System.out.println("Most common: '" + (char) ('a' + best) + "' (" + freq[best] + " times)");
    }
}

s = "programming"
freq = [0] * 26
for c in s:
    freq[ord(c) - ord('a')] += 1
best = freq.index(max(freq))
print(f"Most common: '{chr(ord('a') + best)}' ({freq[best]} times)")

#include <stdio.h>
#include <string.h>
int main() {
    char s[] = "programming";
    int freq[26] = {0};
    for (int i = 0; i < strlen(s); i++) freq[s[i] - 'a']++;
    int best = 0;
    for (int i = 1; i < 26; i++) if (freq[i] > freq[best]) best = i;
    printf("Most common: '%c' (%d times)\n", 'a' + best, freq[best]);
    return 0;
}

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